1The area of triangle PSG, constructed from quadrilateral PQRS, is equal to the area of quadrilateral PQRS. How?
2Construct a triangle ABC in which AB = 2.6 cm, BC = 3.4 cm and CA = 4 cm. Again construct a rectangle whose area is equal to triangle ABC.
3Construct a rectangle equal in area to the triangle XYZ having XY = 4 cm, YZ = 6.8 cm and ZX = 6.5 cm.
4Construct a quadrilateral PQRS in which PQ = QR = 5.5 cm, RS = SP = 4.5 cm and ∠SPQ = 75°. Then construct a triangle PST equal in area to the quadrilateral PQRS.
5Construct a quadrilateral ABCD in which AB = 4.5 cm, BC = 5.5 cm, CD = 5.7 cm, DA = 4.9 cm and diagonal BD = 5.9 cm. Then construct a triangle DAE equal in area to the quadrilateral ABCD.
6Construct a triangle QRT equal in area to the quadrilateral PQRS in which PQ = 5 cm, QR = 7 cm, RS = 4.5 cm, SP = 5.4 cm and QS = 6.5 cm.
7Construct a rhombus PQRS in which the diagonals PR = 6 cm and QS = 8 cm. Then construct a triangle PSA which is equal in area to the rhombus PQRS.
8Construct a triangle whose one angle is 60° and whose area is equal to the rectangle in which length is 6 cm and breadth is 4.5 cm.
9When triangle PSG is made from PQRS, why must the line through R be parallel to SQ and not to PR?
10How many different triangles equal in area to one quadrilateral can be made by this method? Why?
11A triangle has base 10 cm and height 6 cm. If a rectangle equal to it in area is constructed by this method, what are the rectangle's length, breadth and area?
12When the rectangle is made from triangle ABC, why is the midpoint D of BC needed? What happens if the rectangle is started from B instead?